A car starts with velocity 0 m/s and accelerates at 2 m/s^2 for 5 s. The distance covered is:
- 12.5 m
- 26 m
- 50 m
- 25 m
Answer
D) 25 m
s = ut + 12at^2 = 0(5) + 12(2)(5)^2 = 25 m. SLO P-11-B-04 · Application
Physics MCQ · More Kinematics and Projectile Motion MCQs · Practise