A string of length 0.9 m fixed at both ends vibrates in 2 loops. The wavelength is:
- 0.9 m
- 0.45 m
- 1.0 m
- 1.8 m
Answer
A) 0.9 m
Each loop is lambda2: lambda = 2Ln = 0.9 m. SLO P-11-D-10 · Application
Physics MCQ · More Superposition, Stationary Waves and Beats MCQs · Practise