A 12 V source with internal resistance 2 Ω supplies a 4 Ω resistor. The efficiency of the power transfer is:
- 33.3%
- 66.7%
- 50%
- 100%
Answer
B) 66.7%
Efficiency = I^2RI^2(R + r) = RR + r = 66.7%. SLO P-09-E-26 · Understanding
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