In the reaction ^147 N + ^42 He to ^178 O + X, X is:
- a proton ^11 p
- an alpha particle
- a neutron
- an electron
Answer
A) a proton ^11 p
A: 18 = 17 + 1; Z: 9 = 8 + 1. SLO P-11-F-07 · Knowledge
Physics MCQ · More Nuclear and Particle Physics MCQs · Practise