A refrigerator removes 400 J from its contents using 100 J of electrical work. The heat given out to the kitchen is:
- 100 J
- 500 J
- 400 J
- 300 J
Answer
B) 500 J
QH = QC + W = 500 J. SLO P-11-C-17 · Understanding
Physics MCQ · More Heat Engines, Second Law and Entropy MCQs · Practise