A ring of mass 2 kg and radius 0.5 m rotates about its central axis. Its moment of inertia is:
- 0.4 kg m^2
- 0.25 kg m^2
- 1 kg m^2
- 0.5 kg m^2
Answer
D) 0.5 kg m^2
I = MR^2 = 0.5 kg m^2. SLO P-11-B-18 · Application
Physics MCQ · More Circular and Rotational Motion MCQs · Practise