A gas absorbs 800 J of heat and has 100 J of work done on it. The change in its internal energy is: (Use Q = Delta U + W, where Q = heat supplied to the gas and W = work done by the gas.)

  1. 1800 J
  2. 900 J
  3. 450 J
  4. 9000 J
Answer

B) 900 J

Delta U = Q - W = 800 - (-100) = 900 J. SLO P-11-C-08 · Application

Physics MCQ · More Kinetic Theory and First Law of Thermodynamics MCQs · Practise