A gas loses 200 J of heat and has 50 J of work done on it. The change in its internal energy is: (Use Q = Delta U + W, where Q = heat supplied to the gas and W = work done by the gas.)

  1. -75 J
  2. -300 J
  3. -150 J
  4. -1500 J
Answer

C) -150 J

Delta U = Q - W = -200 - (-50) = -150 J. SLO P-11-C-08 · Application

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