A proton (charge 1.6 10^-19 C) moves at 3 10^5 m/s at 30^circ to a field of 0.2 T. The magnetic force on it is:
- 4.8 10^-15 N
- 2.4 10^-15 N
- 4.8 10^-14 N
- 9.6 10^-15 N
Answer
A) 4.8 10^-15 N
F = Bqvsintheta = 4.8 10^-15 N. SLO P-09-E-32 · Application
Physics MCQ · More Magnetism and Electromagnetic Induction MCQs · Practise