A gas at constant pressure 1.5 10^5 Pa changes volume from 0.004 m^3 to 0.001 m^3. The work done by the gas is:
- -45 J
- -450 J
- 450 J
- -4500 J
Answer
B) -450 J
W = pDelta V = 1.5 10^5 (0.001 - 0.004) = -450 J. (Negative: the gas is compressed, so work is done on it.) SLO P-11-C-06 · Application
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