A spring of constant 100 N/m stores 0.5 J of elastic energy. Its extension is:

  1. 0.05 m
  2. 0.2 m
  3. 0.01 m
  4. 0.1 m
Answer

D) 0.1 m

x = 2Ek = 2(0.5)100 = 0.1 m. SLO P-11-B-28 · Application

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