A wire of diameter 0.5 mm carries a load of 500 N. The stress in the wire is:
- 5.09 10^9 Pa
- 1.02 10^10 Pa
- 2.55 10^9 Pa
- 6.37 10^8 Pa
Answer
C) 2.55 10^9 Pa
A = pi r^2 = pi(2.5 10^-4)^2 = 1.96 10^-7 m^2; sigma = F/A = 2.55 10^9 Pa. SLO P-11-B-24 · Application
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