A ship is 8 km east and 8 3 km north of a port. The bearing of the ship from the port is:
- 060^circ
- 120^circ
- 300^circ
- 030^circ
Answer
D) 030^circ
tantheta = east north = 88 3 = 1 3, so theta = 30^circ. SLO M-09-B-27 · Application
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