At a junction, currents of 5 A, 3 A flow in. Currents of 6 A flow out, together with one unknown current I. I is:
- 2 A
- 20 A
- 1 A
- 4 A
Answer
A) 2 A
sum Iin = sum Iout Rightarrow I = 8 - 6 = 2 A. SLO P-09-E-18 · Knowledge
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