A string of length 2 m fixed at both ends vibrates in 4 loops. The wavelength is:
- 0.5 m
- 2 m
- 8 m
- 1 m
Answer
D) 1 m
Each loop is lambda2: lambda = 2Ln = 1 m. SLO P-11-D-10 · Application
Physics MCQ · More Superposition, Stationary Waves and Beats MCQs · Practise