A 6 V source with internal resistance 1 Ω supplies a 5 Ω resistor. The efficiency of the power transfer is:
- 16.7%
- 50%
- 83.3%
- 100%
Answer
C) 83.3%
Efficiency = I^2RI^2(R + r) = RR + r = 83.3%. SLO P-09-E-26 · Understanding
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