A spring's force rises linearly from 10 N at extension 0.02 m to 30 N at 0.06 m. The work done over this range is:

  1. 1.6 J
  2. 0.8 J
  3. 0.4 J
  4. 1.2 J
Answer

B) 0.8 J

Area of the trapezium = 12(10 + 30)(0.06 - 0.02) = 0.8 J. SLO P-11-B-27 · Application

Physics MCQ · More Deformation of Solids MCQs · Practise