A spring of spring constant 50 N/m is stretched by 0.3 m (within the limit of proportionality). The elastic potential energy stored is:

  1. 4.5 J
  2. 2.25 J
  3. 1.12 J
  4. 7.5 J
Answer

B) 2.25 J

Ep = 12kx^2 = 12(50)(0.3)^2 = 2.25 J. SLO P-11-B-28 · Application

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