A ring of mass 4 kg and radius 0.3 m rotates about its central axis. Its moment of inertia is:
- 0.288 kg m^2
- 0.36 kg m^2
- 0.72 kg m^2
- 0.18 kg m^2
Answer
B) 0.36 kg m^2
I = MR^2 = 0.36 kg m^2. SLO P-11-B-18 · Application
Physics MCQ · More Circular and Rotational Motion MCQs · Practise