A torque of 10 N m acts on a wheel with I = 2 kg m^2. Its angular acceleration is:
- 5 rad/s^2
- 2.5 rad/s^2
- 10 rad/s^2
- 20 rad/s^2
Answer
A) 5 rad/s^2
tau = Ialpha Rightarrow alpha = 102 = 5 rad/s^2. SLO P-11-B-19 · Application
Physics MCQ · More Circular and Rotational Motion MCQs · Practise