At a junction, currents of 10 A, 4 A, 1 A flow in. Currents of 7 A, 2 A flow out, together with one unknown current I. I is:
- 6 A
- 12 A
- 60 A
- 3 A
Answer
A) 6 A
sum Iin = sum Iout Rightarrow I = 15 - 9 = 6 A. SLO P-09-E-18 · Knowledge
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