Given log 2 = 0.3010 and log 3 = 0.4771, find log 0.6.

  1. -0.2219
  2. 0.0791
  3. 0.8781
  4. 0.1436
Answer

A) -0.2219

log 0.6 = log 2 + log 3 - log 10 = -0.2219. SLO M-09-A-08 · Application

Mathematics MCQ · More Real Numbers MCQs · Practise