The dimensions of Planck's constant h (from E = hf) are:

  1. [ M L^2 T^-1]
  2. [ M L^2 T^-3]
  3. [ M L T^-1]
  4. [ M L^2 T^-2]
Answer

A) [ M L^2 T^-1]

h = E/f: ML^2T^-2/T^-1 = ML^2T^-1. SLO P-11-A-04 · Application

Physics MCQ · More Physical Quantities and Measurement MCQs · Practise