A ring of mass 10 kg and radius 1 m rotates about its central axis. Its moment of inertia is:
- 10 kg m^2
- 8 kg m^2
- 20 kg m^2
- 5 kg m^2
Answer
A) 10 kg m^2
I = MR^2 = 10 kg m^2. SLO P-11-B-18 · Application
Physics MCQ · More Circular and Rotational Motion MCQs · Practise