A torque of 1.2 N m acts on a wheel with I = 0.4 kg m^2. Its angular acceleration is:
- 6 rad/s^2
- 1.5 rad/s^2
- 0.48 rad/s^2
- 3 rad/s^2
Answer
D) 3 rad/s^2
tau = Ialpha Rightarrow alpha = 1.20.4 = 3 rad/s^2. SLO P-11-B-19 · Application
Physics MCQ · More Circular and Rotational Motion MCQs · Practise