A current of 0.2 A flows through a 100 Ω resistor. The power dissipated is:
- 4 W
- 8 W
- 20 W
- 2 W
Answer
A) 4 W
P = I^2R = (0.2)^2(100) = 4 W. SLO P-09-E-12 · Application
Physics MCQ · More Current Electricity MCQs · Practise
A) 4 W
P = I^2R = (0.2)^2(100) = 4 W. SLO P-09-E-12 · Application
Physics MCQ · More Current Electricity MCQs · Practise