A coil of area 0.1 m^2 is in a 0.8 T field; the field makes 30^circ with the normal to the coil. The flux through the coil is:
- 0.0346 Wb
- 0.693 Wb
- 0.139 Wb
- 0.0693 Wb
Answer
D) 0.0693 Wb
Phi = BAcostheta = 0.8 0.1 cos 30^circ = 0.0693 Wb. SLO P-09-E-39 · Application
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