A 1000 kg body moving at 20 m/s is brought to rest by a constant resistive force in 50 m. The resistive force is:
- 4000 N
- 400 N
- 8000 N
- 2000 N
Answer
A) 4000 N
Work done by friction = loss in KE: fd = 12mu^2 Rightarrow f = 4000 N. SLO P-11-B-32 · Application
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