A ship sails 20 km on a bearing of 035^circ. Using sin 35^circ approx 0.574 and cos 35^circ approx 0.819, it is about:

  1. 16.4 km south and 11.5 km east
  2. 11.5 km north and 16.4 km east
  3. 20 km north and 0 km east
  4. 16.4 km north and 11.5 km east
Answer

D) 16.4 km north and 11.5 km east

North = 20cos 35^circ approx 16.4 km; east = 20sin 35^circ approx 11.5 km. SLO M-09-B-27 · Application

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