A car starts with velocity 10 m/s and accelerates at 3 m/s^2 for 4 s. The distance covered is:
- 88 m
- 64 m
- 32 m
- 128 m
Answer
B) 64 m
s = ut + 12at^2 = 10(4) + 12(3)(4)^2 = 64 m. SLO P-11-B-04 · Application
Physics MCQ · More Kinematics and Projectile Motion MCQs · Practise