A gas at constant pressure 2 10^5 Pa changes volume from 0.01 m^3 to 0.025 m^3. The work done by the gas is:
- -3000 J
- 30,000 J
- 3000 J
- 300 J
Answer
C) 3000 J
W = pDelta V = 2 10^5 (0.025 - 0.01) = 3000 J. SLO P-11-C-06 · Application
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