1000 J of heat is added reversibly at 250 K. The entropy change is:
- 250,000 J/K
- 0.25 J/K
- 1250 J/K
- 4 J/K
Answer
D) 4 J/K
Delta S = 1000/250. SLO P-11-C-18 · Understanding
Physics MCQ · More Heat Engines, Second Law and Entropy MCQs · Practise
D) 4 J/K
Delta S = 1000/250. SLO P-11-C-18 · Understanding
Physics MCQ · More Heat Engines, Second Law and Entropy MCQs · Practise