1 mol of an ideal gas at 273 K occupies 0.0224 m^3. Its pressure is (R = 8.31 J mol^-1 K^-1):
- 1.01 10^5 Pa
- 10,100 Pa
- 1.01 10^6 Pa
- 2.03 10^5 Pa
Answer
A) 1.01 10^5 Pa
P = nRTV = 1 8.31 2730.0224 = 1.01 10^5 Pa. SLO P-11-C-03 · Application
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