1 mol of an ideal gas is heated at constant pressure so its temperature rises by 100 K. The work done by the gas is:
- 416 J
- 1660 J
- 1250 J
- 831 J
Answer
D) 831 J
W = pDelta V = nRDelta T = 1 8.31 100 = 831 J. SLO P-11-C-06 · Application
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