A car starts with velocity 5 m/s and accelerates at 1.5 m/s^2 for 8 s. The distance covered is:

  1. 44 m
  2. 88 m
  3. 136 m
  4. 176 m
Answer

B) 88 m

s = ut + 12at^2 = 5(8) + 12(1.5)(8)^2 = 88 m. SLO P-11-B-04 · Application

Physics MCQ · More Kinematics and Projectile Motion MCQs · Practise