A current (2.0 pm 0.1) A flows through a resistor with p.d. (8.0 pm 0.2) V. The resistance is:

  1. (4.0 pm 0.03) Omega
  2. (4.0 pm 0.5) Omega
  3. (4.0 pm 0.1) Omega
  4. (4.0 pm 0.3) Omega
Answer

D) (4.0 pm 0.3) Omega

5% + 2.5% = 7.5% of 4.0 Omega is 0.3 Omega. SLO P-11-A-06 · Application

Physics MCQ · More Physical Quantities and Measurement MCQs · Practise