A spring of spring constant 800 N/m is stretched by 0.05 m (within the limit of proportionality). The elastic potential energy stored is:

  1. 20 J
  2. 2 J
  3. 1 J
  4. 0.5 J
Answer

C) 1 J

Ep = 12kx^2 = 12(800)(0.05)^2 = 1 J. SLO P-11-B-28 · Application

Physics MCQ · More Deformation of Solids MCQs · Practise