The period T of a simple pendulum depends on its length l and g: T = k,l^ag^b. Then

  1. a = 1, b = -1
  2. a = 12, b = - 12
  3. a = 12, b = 12
  4. a = - 12, b = 12
Answer

B) a = 12, b = - 12

T = L^a( LT^-2)^b: L: a + b = 0; T: -2b = 1. So b = - 12, a = 12, giving T = k l/g. SLO P-11-A-04 · Application

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