A hiker walks 8 km north and then 15 km east. Her distance and bearing from the start are:

  1. 17 km on a bearing of about 028.1^circ
  2. 17 km on a bearing of about 061.9^circ
  3. 17 km on a bearing of about 241.9^circ
  4. 23 km on a bearing of about 061.9^circ
Answer

B) 17 km on a bearing of about 061.9^circ

Distance = 8^2 + 15^2 = 17 km. Bearing = tan^-1 158 approx 61.9^circ (measured from north). SLO M-09-B-27 · Application

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