A proton is accelerated through a p.d. of 1 10^6 V. The kinetic energy it gains is:

  1. 3.2 10^-13 J
  2. 1.6 10^-12 J
  3. 1.6 10^-13 J
  4. 8 10^-14 J
Answer

C) 1.6 10^-13 J

KE = eV = 1.6 10^-19 1 10^6 = 1.6 10^-13 J. SLO P-11-F-23 · Understanding

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