In the proof of (x - 3)^2 + 5 = x^2 - 6x + 14, the first step is:
- (x - 3)^2 = x^2 - 9
- x^2 - 6x + 14 = (x - 3)^2
- (x - 3)^2 = x^2 + 9
- (x - 3)^2 = x^2 - 6x + 9
Answer
D) (x - 3)^2 = x^2 - 6x + 9
Expand the square, then add 5: x^2 - 6x + 9 + 5 = x^2 - 6x + 14. SLO M-09-B-15 · Knowledge
Mathematics MCQ · More Logic MCQs · Practise