Deriving tau = Ialpha: for a particle, F = ma = mralpha, so tau = rF =

  1. mr^2alpha
  2. mr^2omega
  3. mralpha
  4. malpha/r
Answer

A) mr^2alpha

Summing over all particles gives tau = (sum mr^2)alpha = Ialpha. SLO P-11-B-19 · Application

Physics MCQ · More Circular and Rotational Motion MCQs · Practise