A fixed mass of gas at 1.5 10^5 Pa occupies 4 L. At constant temperature it is changed to 6 L. The new pressure is:
- 1 10^5 Pa
- 2 10^5 Pa
- 50,000 Pa
- 2.25 10^5 Pa
Answer
A) 1 10^5 Pa
p1V1 = p2V2 Rightarrow p2 = 1.5 10^5 46 = 1 10^5 Pa. SLO P-11-C-10 · Application
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