A wire of length 0.3 m carries 5 A at 90^circ to a uniform magnetic field of 0.2 T. The force on it is:
- 0.4 N
- 0.3 N
- 0.15 N
- 0.6 N
Answer
B) 0.3 N
F = BILsintheta = 0.2 5 0.3 sin 90^circ = 0.3 N. SLO P-09-E-30 · Application
Physics MCQ · More Magnetism and Electromagnetic Induction MCQs · Practise