If a gravitational wave stretches a 4 km detector arm by 10^-18 m, the strain is about:
- 10^-18
- 2.5 10^-22
- 4 10^3
- 4 10^-15
Answer
B) 2.5 10^-22
Strain = Delta LL = 10^-184000. SLO P-11-D-19 · Knowledge
Physics MCQ · More Gravitational Waves MCQs · Practise