A refrigerator removes 900 J from its contents using 300 J of electrical work. The heat given out to the kitchen is:
- 1200 J
- 300 J
- 900 J
- 600 J
Answer
A) 1200 J
QH = QC + W = 1200 J. SLO P-11-C-17 · Understanding
Physics MCQ · More Heat Engines, Second Law and Entropy MCQs · Practise