Verify the distributive law of union over intersection: with A = 1, 2, 5, 6, 7, B = 1, 5, 7, 10, C = 2, 3, 5, 7, both A cup (B cap C) and (A cup B) cap (A cup C) equal:

  1. 1, 2, 3, 5, 6, 7, 10
  2. 2, 5, 7
  3. 1, 2, 5, 6, 7
  4. 5, 7
Answer

C) 1, 2, 5, 6, 7

Working out each side separately gives the same set 1, 2, 5, 6, 7, which verifies A cup (B cap C) = (A cup B) cap (A cup C). SLO M-09-A-13 · Application

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