A gas absorbs 300 J of heat and does 300 J of work. The change in its internal energy is: (Use Q = Delta U + W, where Q = heat supplied to the gas and W = work done by the gas.)

  1. 600 J
  2. 0 J
  3. 100 J
  4. 50 J
Answer

B) 0 J

Delta U = Q - W = 300 - (300) = 0 J. SLO P-11-C-08 · Application

Physics MCQ · More Kinetic Theory and First Law of Thermodynamics MCQs · Practise