Show that the square of any odd number 2n + 1 is odd:

  1. (2n + 1)^2 = 2(2n^2 + 1)
  2. (2n + 1)^2 = 4n^2 + 1
  3. (2n + 1)^2 = 2(2n^2 + 2n) + 1
  4. (2n + 1)^2 = 2n^2 + 1
Answer

C) (2n + 1)^2 = 2(2n^2 + 2n) + 1

(2n + 1)^2 = 4n^2 + 4n + 1 = 2(2n^2 + 2n) + 1: twice an integer, plus one. SLO M-09-B-15 · Knowledge

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