A 0.05 kg body moves at 400 m/s. Its kinetic energy is:
- 10 J
- 4000 J
- 2000 J
- 8000 J
Answer
B) 4000 J
K = 12mv^2 = 12(0.05)(400)^2 = 4000 J. SLO P-11-B-29 · Application
Physics MCQ · More Work and Energy MCQs · Practise
B) 4000 J
K = 12mv^2 = 12(0.05)(400)^2 = 4000 J. SLO P-11-B-29 · Application
Physics MCQ · More Work and Energy MCQs · Practise